36k^2-16=0

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Solution for 36k^2-16=0 equation: 



36k^2-16=0

a = 36; b = 0; c = -16;
Δ = b2-4ac
Δ = 02-4·36·(-16)
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$


$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-48}{2*36}=\frac{-48}{72}
=-2/3
$


$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+48}{2*36}=\frac{48}{72}
=2/3
$

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